vault backup: 2023-03-17 10:17:22

AMiAL/Ćwiczenia/2 SEM/20230303081617.md

@@ -1,2 +1,3 @@
 //O zgrozo
 
+// Całki

AMiAL/Ćwiczenia/Zadania/Całki/Zadanie 1.md

@@ -12,14 +12,17 @@ $$\int\left(\frac{3}{x^{2}}+\frac{4}{x^{3}}\right)dx=\int\frac{3}{x^{2}}dx+\int\
 ## 6
 $$\begin{gathered}
 
-\int\frac{(3-x)^{2}}{x^{3}}dx=\int\frac{9-6x+x^{2}}{x^{3}}dx=\int\frac{9}{x^{3}}dx+\int\frac{-6x}{x^3}dx+\int\frac{x^{2}}{x^{3}}dx=
-\newline
-\newline
+\int\frac{(3-x)^{2}}{x^{3}}dx=\int\frac{9-6x+x^{2}}{x^{3}}dx=\int\frac{9}{x^{3}}dx+\int\frac{-6x}{x^3}dx+\int\frac{x^{2}}{x^{3}}dx\\
+=
 9\ln|x^{3}|-6\ln|x^2|+\ln|x|+C
 \end{gathered}
 $$
 ## 7
-$$\int\frac{1-x^{2}}{x^{3}}dx=\int\frac{1}{x^{3}}dx+\int-\frac{x^{2}}{x^{3}}dx=\ln|x^{3}|-\ln|x|$$
+$$\int\frac{1-x^{2}}{x^{3}}dx=\int\frac{1}{x^{3}}dx+\int-\frac{x^{2}}{x^{3}}dx=\ln|x^{3}|-\ln|x|+C$$
+## 8.
+$$\begin{gather}
+\int \frac{x^{4}-4}{x^{2}+2}dx=\int \frac{(x^{2}+2)(x^{2}-2)}{x^{2}+2}dx=\int x^{2}-2dx=\frac{x^{3}}{3}-2x+C
+\end{gather}$$
 
 ## 9.
 $$\int x\sqrt{x}\ dx=
@@ -28,5 +31,25 @@ $$\int x\sqrt{x}\ dx=
 $$
 \int x\sqrt[4]{x^{3}}dx = \int\sqrt[4]{x^{7}}dx=\int x^{\frac{7}{4}}dx=\frac{x^{\frac{11}{4}}}{\frac{11}{4}}+C=\frac{4x^{\frac{11}{4}}}{11}+C=\frac{8\sqrt[4]{x^{3}}}{11}+C
 $$
+## 11.
+$$
+\begin{gather}
+\int \sqrt{x}(\frac{1}{x}+x)dx=\int \frac{\sqrt{x}}{x}+x\sqrt{x}\ dx=\int x^{-\frac{1}{2}}+x^\frac{3}{2}dx=2x^\frac{1}{2}+\frac{2x^{\frac{5}{2}}}{5}+C\\
+= \frac{10x^\frac{1}{2}+2x^{\frac{5}{2}}}{5}+C
+\end{gather}
+$$
+## 12.
+$$
+\begin{gather}
+\int \sqrt{x\sqrt{x}}\ dx=\int (x^{\frac{3}{2}})^{\frac{1}{2}}dx=\int x^{\frac{3}{4}}dx=\frac{4x^{\frac{7}{4}}}{7}+C
+\end{gather}
+
+$$
+## 13.
+$$
+\begin{gather}
+\int \frac{1}{\sqrt[3]{x^{2}}}dx=\int\sqrt[3]{x^{2}}^{-1}dx=\int ((x^{2})^{\frac{1}{3}})^{-1}dx=\int x^{-\frac{2}{3}}dx=3x^{\frac{1}{3}}+C
+\end{gather}
+$$
 ## 18.
 $$\int (4^{x}+2^{-x})dx=\frac{4x}{\ln 4}+ \int (\frac{1}{2})^{x}dx=\frac{4^{x}}{\ln 4}+\frac{(\frac{1}{2})^{x}}{\ln \frac{1}{2}}+c$$