vault backup: 2023-03-10 13:18:37
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TIiK/Ćwiczenia/1. Logarytmy.md
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TIiK/Ćwiczenia/1. Logarytmy.md
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---
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Date: [20230310121338]
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---
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![[1. Logarytmy 2023-03-10 12.15.12.excalidraw]]
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$$U[U] \rightarrow 20\log[\frac{U}{U}]
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$$
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$$\begin{align}
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-60dB \rightarrow 0.001 \left[\frac{U}{U}\right]\\
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-40dB \rightarrow 0.01 \left[\frac{U}{U}\right]\\
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-20dB \rightarrow 0.1 \left[\frac{U}{U}\right]\\
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-3dB \rightarrow \sqrt{2} \left[\frac{U}{U}\right]\\
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0dB \rightarrow 1 \left[\frac{U}{U}\right]\\
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3dB \rightarrow \sqrt{2} \left[\frac{U}{U}\right]\\
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20dB \rightarrow 10 \left[\frac{U}{U}\right]\\
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40dB \rightarrow 100 \left[\frac{U}{U}\right]\\
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100dB \rightarrow 10^{5} \left[\frac{U}{U}\right]\\
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\end{align}$$
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Kaskada = sumowanie wzmocnień
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30 10
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-\[\]-\[\]-
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--\[\]--
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40
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![[1. Logarytmy 2023-03-10 13.02.53.excalidraw]]
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![[1. Logarytmy 2023-03-10 13.04.21.excalidraw]]
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![[1. Logarytmy 2023-03-10 13.10.03.excalidraw]]
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$$ \begin{align}
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0dB &\rightarrow 1 \left[\frac{W}{W}\right]\\
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3dB &\rightarrow 2 \left[\frac{W}{W}\right]\\
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10dB &\rightarrow 10 \left[\frac{W}{W}\right]\\
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20dB &\rightarrow 100 \left[\frac{W}{W}\right]\\
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30dB &\rightarrow 1000 \left[\frac{W}{W}\right]\\
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\end{align}
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$$
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2.11)
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Jedna z 10 żarówek uległa przepaleniu. Mając do dyspozycji woltomierz wykryj żarówkę. Przepalenie każdej jest jednakowo prawdopodobne.
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