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Polsl-Notes/Elektrotechnika/Ćwiczenia/20230526102526.md

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K(S)=\frac{1}{1+ST} K(j\omega)=\frac{1}{1+j\omega T} |K(j\omega)|=K(\omega)=K=\frac{1}{\sqrt{1^{2}+(\omega T)^{2}}}

\phi(\omega)=0\degree - \arctan(\frac{\omega T}{1})

- K \phi
\omega=0 1 0\degree
\omega=\frac{1}{T} \frac{1}{\sqrt{2}} -45\degree
\omega\rightarrow\infty 0 -90\degree