96 B
96 B
$$\begin{aligned} \frac{16-3i}{7+2i}-3&=\frac{106-53i}{53}-3\ 2-i-3&=-1-i\
\end{aligned}$$
$$\begin{aligned} \frac{16-3i}{7+2i}-3&=\frac{106-53i}{53}-3\ 2-i-3&=-1-i\
\end{aligned}$$