vault backup: 2023-05-26 10:39:08
This commit is contained in:
28
.obsidian/workspace.json
vendored
28
.obsidian/workspace.json
vendored
@@ -13,24 +13,13 @@
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"state": {
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"type": "markdown",
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"state": {
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"file": "AMiAL/AMiAL.md",
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"file": "Elektrotechnika/Ćwiczenia/20230526102526.md",
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"mode": "source",
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"source": false
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}
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}
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},
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{
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"id": "c4a38d3c79d59253",
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"type": "leaf",
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"state": {
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"type": "release-notes",
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"state": {
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"currentVersion": "1.3.4"
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}
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}
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}
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],
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"currentTab": 1
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]
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}
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],
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"direction": "vertical"
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@@ -104,7 +93,7 @@
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"state": {
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"type": "backlink",
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"state": {
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"file": "AMiAL/AMiAL.md",
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"file": "Elektrotechnika/Ćwiczenia/20230526102526.md",
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"collapseAll": false,
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"extraContext": false,
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"sortOrder": "alphabetical",
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@@ -121,7 +110,7 @@
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"state": {
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"type": "outgoing-link",
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"state": {
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"file": "AMiAL/AMiAL.md",
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"file": "Elektrotechnika/Ćwiczenia/20230526102526.md",
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"linksCollapsed": false,
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"unlinkedCollapsed": true
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}
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@@ -144,7 +133,7 @@
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"state": {
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"type": "outline",
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"state": {
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"file": "AMiAL/AMiAL.md"
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"file": "Elektrotechnika/Ćwiczenia/20230526102526.md"
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}
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}
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},
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@@ -226,11 +215,13 @@
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"3d-graph:3D Graph": false,
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"juggl:Juggl global graph": false,
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"random-note:Open random note": false,
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"obsidian-excalidraw-plugin:Create new drawing": false
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"obsidian-excalidraw-plugin:Create new drawing": false,
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"breadcrumbs:Breadcrumbs Visualisation": false
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}
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},
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"active": "c4a38d3c79d59253",
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"active": "4f3b7a6eabb0779a",
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"lastOpenFiles": [
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"Elektrotechnika/Ćwiczenia/20230526102526.md",
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"AiSD/AiSD.md",
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"TC/Wykład/8. Przerzutniki.md",
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"TC/Wykład/7..md",
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@@ -257,7 +248,6 @@
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"TC/Ćwiczenia/3. Układy iteracyjne.md",
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"TC/Laboratorium/Laboratorium.md",
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"!Załączniki/2. Charakterystyki 2023-04-25 13.49.32.excalidraw.md",
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"EiM/Ćwiczenia/2. Charakterystyki.md",
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"!Załączniki/Recording 20230418135018.webm",
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"!Załączniki/Recording 20230418134959.webm",
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"EiM/Ćwiczenia",
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10
Elektrotechnika/Ćwiczenia/20230526102526.md
Normal file
10
Elektrotechnika/Ćwiczenia/20230526102526.md
Normal file
@@ -0,0 +1,10 @@
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$K(S)=\frac{1}{1+ST}$
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$K(j\omega)=\frac{1}{1+j\omega T}$
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$|K(j\omega)|=K(\omega)=K=\frac{1}{\sqrt{1^{2}+(\omega T)^{2}}}$
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$\phi(\omega)=0\degree - \arctan(\frac{\omega T}{1})$
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|-|$K$|$\phi$|
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|-|-|-|
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|$\omega=0$|$1$|$0\degree$|
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|$\omega=\frac{1}{T}$|$\frac{1}{\sqrt{2}}$|$-45\degree$|
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|$\omega\rightarrow\infty$|$0$|$-90\degree$|
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