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Polsl-Notes/AMiAL/ICT/Ćwiczenia/1 SEM/20221118121118.md

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$$\begin{aligned}
a_n&=n^{2}-8n+15\\
a_{n+1}&=(n+1)^{2} - 8(n+1)+15 \\
a_{n+1}&=n^{2}-6n+8 \\
a_{n+1}-a_{n}&=(n^{2}-6n+8)-(n^{2}-8n +15)\\
a_{n+1}-a_{n}&=2n-7
\end{aligned}$$
Ciąg jest niemonotoniczny, ponieważ znaki się zmieniają w jego trakcie.