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Polsl-Notes/Elektrotechnika/Ćwiczenia/20230526102526.md

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$K(S)=\frac{1}{1+ST}$
$K(j\omega)=\frac{1}{1+j\omega T}$
$|K(j\omega)|=K(\omega)=K=\frac{1}{\sqrt{1^{2}+(\omega T)^{2}}}$
$\phi(\omega)=0\degree - \arctan(\frac{\omega T}{1})$
|-|$K$|$\phi$|
|-|-|-|
|$\omega=0$|$1$|$0\degree$|
|$\omega=\frac{1}{T}$|$\frac{1}{\sqrt{2}}$|$-45\degree$|
|$\omega\rightarrow\infty$|$0$|$-90\degree$|